topic ION 7650 energy calculation in Metering & Power Quality
https://community.exchange.se.com/t5/Metering-Power-Quality/ION-7650-energy-calculation/m-p/274036#M5520
<P>Hello experts,</P><P> </P><P>I have a customer asking about how ION Meter do energy calculations. He made a manual calculation to compare energy calculated manually to meter calculation as image attached.</P><P> </P><P>Just the "error" and "Intervalo de energía activa CALCULADA" columns are calculated, the other ones are using ION meter variables outputs took from PME.</P><P> </P><P>The formula used by customer for manual energy was:</P><P> </P><P>((SUM of three phase currents* AVG Three Phase Voltage * ^3 * Power Factor)/4000) It is also a image attached "formula"</P><P> </P><P>The customer now is asking me why is a big difference between calculations and measured value. I wonder if you can help me to justificate technically that ION meter is calculating in the proper way.</P><P> </P><P>Thanks!</P>Thu, 29 Apr 2021 19:03:39 GMTjoel_mora_soati2021-04-29T19:03:39ZION 7650 energy calculation
https://community.exchange.se.com/t5/Metering-Power-Quality/ION-7650-energy-calculation/m-p/274036#M5520
<P>Hello experts,</P><P> </P><P>I have a customer asking about how ION Meter do energy calculations. He made a manual calculation to compare energy calculated manually to meter calculation as image attached.</P><P> </P><P>Just the "error" and "Intervalo de energía activa CALCULADA" columns are calculated, the other ones are using ION meter variables outputs took from PME.</P><P> </P><P>The formula used by customer for manual energy was:</P><P> </P><P>((SUM of three phase currents* AVG Three Phase Voltage * ^3 * Power Factor)/4000) It is also a image attached "formula"</P><P> </P><P>The customer now is asking me why is a big difference between calculations and measured value. I wonder if you can help me to justificate technically that ION meter is calculating in the proper way.</P><P> </P><P>Thanks!</P>Thu, 29 Apr 2021 19:03:39 GMThttps://community.exchange.se.com/t5/Metering-Power-Quality/ION-7650-energy-calculation/m-p/274036#M5520joel_mora_soati2021-04-29T19:03:39ZRe: ION 7650 energy calculation
https://community.exchange.se.com/t5/Metering-Power-Quality/ION-7650-energy-calculation/m-p/274048#M5521
<P>Hello <LI-USER uid="9534"></LI-USER>,</P>
<P> </P>
<P>Moved the question to the metering forum</P>
<P>The direct question, how does the ION7650 calculate energy? This is done by integrating the power every second. Have a look at the ION Reference Integrator module for more information.</P>
<P> </P>
<P>Regarding your equation, there are a few unknowns like what volts mode does the ION7650 meter have, what version of firmware, what template, what setting for the kVA summation. I will assume you have a 4w wye system.</P>
<P> <BR />In a Wye system, kW total = kW a + kW b + kW c, where kW a ~= Ia * VLN a * PF, since we do not have VLN a, I will estimate VLN A ~= VLL AB / SQRT(3), repeat for each phase. </P>
<P> </P>
<P>It looks to me like formula should be <FONT size="5"><STRONG>/</STRONG></FONT>RAIZ(3) and not <FONT size="5"><STRONG>*</STRONG></FONT>RAIZ(3)</P>
<P> </P>
<P>If you have a Delta system the math would be different as there would be a 2 watt meters. to calculate power.</P>
<P> </P>
<P>Regards,</P>
<P>Charles</P>Thu, 29 Apr 2021 21:11:44 GMThttps://community.exchange.se.com/t5/Metering-Power-Quality/ION-7650-energy-calculation/m-p/274048#M5521Charles_Murison2021-04-29T21:11:44ZRe: ION 7650 energy calculation
https://community.exchange.se.com/t5/Metering-Power-Quality/ION-7650-energy-calculation/m-p/274050#M5522
<P>Thanks <LI-USER uid="27891"></LI-USER> </P><P> </P><P>It is very clear for me.</P><P> </P><P>Refering to the manual calculation, to calculate the active power which of the meter measurements are correct to use:<BR /><BR />- Current X Mean (sum the 3 phases) or Current Avg Mean? =>>>>> (Let say this is I in the formula below)<BR />- Voltage X Mean (Average of 3 phases) or Voltage LL Avg Mean? =>>>>(Let say this is V in the formula below)</P><P> </P><P>As you said, the proper way to calculate will be:<BR /><BR />kW = I*(V/SQRT(3))*PF</P><P> </P><P>I really apreciate your help, thanks.</P>Thu, 29 Apr 2021 21:30:13 GMThttps://community.exchange.se.com/t5/Metering-Power-Quality/ION-7650-energy-calculation/m-p/274050#M5522joel_mora_soati2021-04-29T21:30:13ZRe: ION 7650 energy calculation
https://community.exchange.se.com/t5/Metering-Power-Quality/ION-7650-energy-calculation/m-p/274059#M5523
<P>Hello <LI-USER uid="9534"></LI-USER> ,</P>
<P> </P>
<P>The example provided is very simplified, this assumes steady-state, sinusoidal signals. The calculation in general and voltage specifically would depend on what volts mode the system is. Note that the meter likely also logged the power demand. </P>
<P> </P>
<P>In general</P>
<DIV>
<DIV>P = S x PF</DIV>
<DIV>where S = V x I, and PF = P / S<BR />
<DIV>
<DIV><BR />P = active power</DIV>
<DIV>S = apparent power</DIV>
</DIV>
<BR />Regards,</DIV>
<DIV>Charles</DIV>
</DIV>Thu, 29 Apr 2021 22:39:42 GMThttps://community.exchange.se.com/t5/Metering-Power-Quality/ION-7650-energy-calculation/m-p/274059#M5523Charles_Murison2021-04-29T22:39:42Z